12-(4x-18)=(36+4x)+(18+6x)

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Solution for 12-(4x-18)=(36+4x)+(18+6x) equation: 



12-(4x-18)=(36+4x)+(18+6x)

We move all terms to the left:

12-(4x-18)-((36+4x)+(18+6x))=0

We add all the numbers together, and all the variables

-(4x-18)-((4x+36)+(6x+18))+12=0

We get rid of parentheses

-4x-((4x+36)+(6x+18))+18+12=0



We calculate terms in parentheses: -((4x+36)+(6x+18)), so:

(4x+36)+(6x+18)

We get rid of parentheses

4x+6x+36+18

We add all the numbers together, and all the variables

10x+54

Back to the equation:

-(10x+54)



We add all the numbers together, and all the variables

-4x-(10x+54)+30=0

We get rid of parentheses

-4x-10x-54+30=0

We add all the numbers together, and all the variables

-14x-24=0

We move all terms containing x to the left, all other terms to the right

-14x=24

x=24/-14

x=-1+5/7

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