12-(4x-18)=(36+4x)=(18-6x)

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Solution for 12-(4x-18)=(36+4x)=(18-6x) equation: 



12-(4x-18)=(36+4x)=(18-6x)

We move all terms to the left:

12-(4x-18)-((36+4x))=0

We add all the numbers together, and all the variables

-(4x-18)-((4x+36))+12=0

We get rid of parentheses

-4x-((4x+36))+18+12=0



We calculate terms in parentheses: -((4x+36)), so:

(4x+36)

We get rid of parentheses

4x+36

Back to the equation:

-(4x+36)



We add all the numbers together, and all the variables

-4x-(4x+36)+30=0

We get rid of parentheses

-4x-4x-36+30=0

We add all the numbers together, and all the variables

-8x-6=0

We move all terms containing x to the left, all other terms to the right

-8x=6

x=6/-8

x=-3/4

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