12-(4x-28)=(37+4x)+(18-6x)

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Solution for 12-(4x-28)=(37+4x)+(18-6x) equation: 



12-(4x-28)=(37+4x)+(18-6x)

We move all terms to the left:

12-(4x-28)-((37+4x)+(18-6x))=0

We add all the numbers together, and all the variables

-(4x-28)-((4x+37)+(-6x+18))+12=0

We get rid of parentheses

-4x-((4x+37)+(-6x+18))+28+12=0



We calculate terms in parentheses: -((4x+37)+(-6x+18)), so:

(4x+37)+(-6x+18)

We get rid of parentheses

4x-6x+37+18

We add all the numbers together, and all the variables

-2x+55

Back to the equation:

-(-2x+55)



We add all the numbers together, and all the variables

-4x-(-2x+55)+40=0

We get rid of parentheses

-4x+2x-55+40=0

We add all the numbers together, and all the variables

-2x-15=0

We move all terms containing x to the left, all other terms to the right

-2x=15

x=15/-2

x=-7+1/2

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