12-(4x-7)-33=8(7x+1)

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Solution for 12-(4x-7)-33=8(7x+1) equation: 



12-(4x-7)-33=8(7x+1)

We move all terms to the left:

12-(4x-7)-33-(8(7x+1))=0

We add all the numbers together, and all the variables

-(4x-7)-(8(7x+1))-21=0

We get rid of parentheses

-4x-(8(7x+1))+7-21=0



We calculate terms in parentheses: -(8(7x+1)), so:

8(7x+1)

We multiply parentheses

56x+8

Back to the equation:

-(56x+8)



We add all the numbers together, and all the variables

-4x-(56x+8)-14=0

We get rid of parentheses

-4x-56x-8-14=0

We add all the numbers together, and all the variables

-60x-22=0

We move all terms containing x to the left, all other terms to the right

-60x=22

x=22/-60

x=-11/30

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