12-(8-2x)=4x-(16+6x)

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Solution for 12-(8-2x)=4x-(16+6x) equation: 



12-(8-2x)=4x-(16+6x)

We move all terms to the left:

12-(8-2x)-(4x-(16+6x))=0

We add all the numbers together, and all the variables

-(-2x+8)-(4x-(6x+16))+12=0

We get rid of parentheses

2x-(4x-(6x+16))-8+12=0



We calculate terms in parentheses: -(4x-(6x+16)), so:

4x-(6x+16)

We get rid of parentheses

4x-6x-16

We add all the numbers together, and all the variables

-2x-16

Back to the equation:

-(-2x-16)



We add all the numbers together, and all the variables

2x-(-2x-16)+4=0

We get rid of parentheses

2x+2x+16+4=0

We add all the numbers together, and all the variables

4x+20=0

We move all terms containing x to the left, all other terms to the right

4x=-20

x=-20/4

x=-5

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