12-(x+2)=4(x-5)

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Solution for 12-(x+2)=4(x-5) equation: 



12-(x+2)=4(x-5)

We move all terms to the left:

12-(x+2)-(4(x-5))=0

We get rid of parentheses

-x-(4(x-5))-2+12=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

-1x-(4x-20)+10=0

We get rid of parentheses

-1x-4x+20+10=0

We add all the numbers together, and all the variables

-5x+30=0

We move all terms containing x to the left, all other terms to the right

-5x=-30

x=-30/-5

x=+6

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