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12-(x+2)=4(x-5)
We move all terms to the left:
12-(x+2)-(4(x-5))=0
We get rid of parentheses
-x-(4(x-5))-2+12=0
We calculate terms in parentheses: -(4(x-5)), so:We add all the numbers together, and all the variables
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
-1x-(4x-20)+10=0
We get rid of parentheses
-1x-4x+20+10=0
We add all the numbers together, and all the variables
-5x+30=0
We move all terms containing x to the left, all other terms to the right
-5x=-30
x=-30/-5
x=+6
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