12-(z+4)=18+z

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Solution for 12-(z+4)=18+z equation: 



12-(z+4)=18+z

We move all terms to the left:

12-(z+4)-(18+z)=0

We add all the numbers together, and all the variables

-(z+4)-(z+18)+12=0

We get rid of parentheses

-z-z-4-18+12=0

We add all the numbers together, and all the variables

-2z-10=0

We move all terms containing z to the left, all other terms to the right

-2z=10

z=10/-2

z=-5

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