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12-1/5r=2r
We move all terms to the left:
12-1/5r-(2r)=0
Domain of the equation: 5r!=0We add all the numbers together, and all the variables
r!=0/5
r!=0
r∈R
-2r-1/5r+12=0
We multiply all the terms by the denominator
-2r*5r+12*5r-1=0
Wy multiply elements
-10r^2+60r-1=0
a = -10; b = 60; c = -1;
Δ = b2-4ac
Δ = 602-4·(-10)·(-1)
Δ = 3560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3560}=\sqrt{4*890}=\sqrt{4}*\sqrt{890}=2\sqrt{890}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{890}}{2*-10}=\frac{-60-2\sqrt{890}}{-20} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{890}}{2*-10}=\frac{-60+2\sqrt{890}}{-20} $
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