12-10(t+2)=t+3

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Solution for 12-10(t+2)=t+3 equation: 



12-10(t+2)=t+3

We move all terms to the left:

12-10(t+2)-(t+3)=0

We multiply parentheses

-10t-(t+3)-20+12=0

We get rid of parentheses

-10t-t-3-20+12=0

We add all the numbers together, and all the variables

-11t-11=0

We move all terms containing t to the left, all other terms to the right

-11t=11

t=11/-11

t=-1

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