12-2(g-7)=3G+3(g+4)

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Solution for 12-2(g-7)=3G+3(g+4) equation: 



12-2(g-7)=3+3(g+4)

We move all terms to the left:

12-2(g-7)-(3+3(g+4))=0

We multiply parentheses

-2g-(3+3(g+4))+14+12=0



We calculate terms in parentheses: -(3+3(g+4)), so:

3+3(g+4)

determiningTheFunctionDomain
3(g+4)+3

We multiply parentheses

3g+12+3

We add all the numbers together, and all the variables

3g+15

Back to the equation:

-(3g+15)



We add all the numbers together, and all the variables

-2g-(3g+15)+26=0

We get rid of parentheses

-2g-3g-15+26=0

We add all the numbers together, and all the variables

-5g+11=0

We move all terms containing g to the left, all other terms to the right

-5g=-11

g=-11/-5

g=2+1/5

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