12-2(w+1)=4w-2(4+w)

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Solution for 12-2(w+1)=4w-2(4+w) equation: 



12-2(w+1)=4w-2(4+w)

We move all terms to the left:

12-2(w+1)-(4w-2(4+w))=0

We add all the numbers together, and all the variables

-2(w+1)-(4w-2(w+4))+12=0

We multiply parentheses

-2w-(4w-2(w+4))-2+12=0



We calculate terms in parentheses: -(4w-2(w+4)), so:

4w-2(w+4)

We multiply parentheses

4w-2w-8

We add all the numbers together, and all the variables

2w-8

Back to the equation:

-(2w-8)



We add all the numbers together, and all the variables

-2w-(2w-8)+10=0

We get rid of parentheses

-2w-2w+8+10=0

We add all the numbers together, and all the variables

-4w+18=0

We move all terms containing w to the left, all other terms to the right

-4w=-18

w=-18/-4

w=4+1/2

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