12-2(x+1)+3x=16

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Solution for 12-2(x+1)+3x=16 equation: 



12-2(x+1)+3x=16

We move all terms to the left:

12-2(x+1)+3x-(16)=0

We add all the numbers together, and all the variables

3x-2(x+1)-4=0

We multiply parentheses

3x-2x-2-4=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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