12-2(x+4)=22(x+2)-13

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Solution for 12-2(x+4)=22(x+2)-13 equation: 



12-2(x+4)=22(x+2)-13

We move all terms to the left:

12-2(x+4)-(22(x+2)-13)=0

We multiply parentheses

-2x-(22(x+2)-13)-8+12=0



We calculate terms in parentheses: -(22(x+2)-13), so:

22(x+2)-13

We multiply parentheses

22x+44-13

We add all the numbers together, and all the variables

22x+31

Back to the equation:

-(22x+31)



We add all the numbers together, and all the variables

-2x-(22x+31)+4=0

We get rid of parentheses

-2x-22x-31+4=0

We add all the numbers together, and all the variables

-24x-27=0

We move all terms containing x to the left, all other terms to the right

-24x=27

x=27/-24

x=-1+1/8

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