12-2(y+3)=4(y-6)-(y-15)

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Solution for 12-2(y+3)=4(y-6)-(y-15) equation: 



12-2(y+3)=4(y-6)-(y-15)

We move all terms to the left:

12-2(y+3)-(4(y-6)-(y-15))=0

We multiply parentheses

-2y-(4(y-6)-(y-15))-6+12=0



We calculate terms in parentheses: -(4(y-6)-(y-15)), so:

4(y-6)-(y-15)

We multiply parentheses

4y-(y-15)-24

We get rid of parentheses

4y-y+15-24

We add all the numbers together, and all the variables

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

-2y-(3y-9)+6=0

We get rid of parentheses

-2y-3y+9+6=0

We add all the numbers together, and all the variables

-5y+15=0

We move all terms containing y to the left, all other terms to the right

-5y=-15

y=-15/-5

y=+3

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