12-3(2g+1)=4g+2-3g

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Solution for 12-3(2g+1)=4g+2-3g equation: 



12-3(2g+1)=4g+2-3g

We move all terms to the left:

12-3(2g+1)-(4g+2-3g)=0

We add all the numbers together, and all the variables

-3(2g+1)-(g+2)+12=0

We multiply parentheses

-6g-(g+2)-3+12=0

We get rid of parentheses

-6g-g-2-3+12=0

We add all the numbers together, and all the variables

-7g+7=0

We move all terms containing g to the left, all other terms to the right

-7g=-7

g=-7/-7

g=1

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