12-3(2w+1)=6w-3(7+w)

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Solution for 12-3(2w+1)=6w-3(7+w) equation: 



12-3(2w+1)=6w-3(7+w)

We move all terms to the left:

12-3(2w+1)-(6w-3(7+w))=0

We add all the numbers together, and all the variables

-3(2w+1)-(6w-3(w+7))+12=0

We multiply parentheses

-6w-(6w-3(w+7))-3+12=0



We calculate terms in parentheses: -(6w-3(w+7)), so:

6w-3(w+7)

We multiply parentheses

6w-3w-21

We add all the numbers together, and all the variables

3w-21

Back to the equation:

-(3w-21)



We add all the numbers together, and all the variables

-6w-(3w-21)+9=0

We get rid of parentheses

-6w-3w+21+9=0

We add all the numbers together, and all the variables

-9w+30=0

We move all terms containing w to the left, all other terms to the right

-9w=-30

w=-30/-9

w=3+1/3

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