12-3(2x-8)-8x=6x+4(7-3x)

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Solution for 12-3(2x-8)-8x=6x+4(7-3x) equation: 



12-3(2x-8)-8x=6x+4(7-3x)

We move all terms to the left:

12-3(2x-8)-8x-(6x+4(7-3x))=0

We add all the numbers together, and all the variables

-3(2x-8)-8x-(6x+4(-3x+7))+12=0

We add all the numbers together, and all the variables

-8x-3(2x-8)-(6x+4(-3x+7))+12=0

We multiply parentheses

-8x-6x-(6x+4(-3x+7))+24+12=0



We calculate terms in parentheses: -(6x+4(-3x+7)), so:

6x+4(-3x+7)

We multiply parentheses

6x-12x+28

We add all the numbers together, and all the variables

-6x+28

Back to the equation:

-(-6x+28)



We add all the numbers together, and all the variables

-14x-(-6x+28)+36=0

We get rid of parentheses

-14x+6x-28+36=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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