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12-3(3x-5)=12(2x+1)
We move all terms to the left:
12-3(3x-5)-(12(2x+1))=0
We multiply parentheses
-9x-(12(2x+1))+15+12=0
We calculate terms in parentheses: -(12(2x+1)), so:We add all the numbers together, and all the variables
12(2x+1)
We multiply parentheses
24x+12
Back to the equation:
-(24x+12)
-9x-(24x+12)+27=0
We get rid of parentheses
-9x-24x-12+27=0
We add all the numbers together, and all the variables
-33x+15=0
We move all terms containing x to the left, all other terms to the right
-33x=-15
x=-15/-33
x=5/11
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