12-3(4x+1)=25-4(5x-1)

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Solution for 12-3(4x+1)=25-4(5x-1) equation: 



12-3(4x+1)=25-4(5x-1)

We move all terms to the left:

12-3(4x+1)-(25-4(5x-1))=0

We multiply parentheses

-12x-(25-4(5x-1))-3+12=0



We calculate terms in parentheses: -(25-4(5x-1)), so:

25-4(5x-1)

determiningTheFunctionDomain
-4(5x-1)+25

We multiply parentheses

-20x+4+25

We add all the numbers together, and all the variables

-20x+29

Back to the equation:

-(-20x+29)



We add all the numbers together, and all the variables

-12x-(-20x+29)+9=0

We get rid of parentheses

-12x+20x-29+9=0

We add all the numbers together, and all the variables

8x-20=0

We move all terms containing x to the left, all other terms to the right

8x=20

x=20/8

x=2+1/2

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