12-3(y-2)=3+5(2-y)

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Solution for 12-3(y-2)=3+5(2-y) equation: 



12-3(y-2)=3+5(2-y)

We move all terms to the left:

12-3(y-2)-(3+5(2-y))=0

We add all the numbers together, and all the variables

-3(y-2)-(3+5(-1y+2))+12=0

We multiply parentheses

-3y-(3+5(-1y+2))+6+12=0



We calculate terms in parentheses: -(3+5(-1y+2)), so:

3+5(-1y+2)

determiningTheFunctionDomain
5(-1y+2)+3

We multiply parentheses

-5y+10+3

We add all the numbers together, and all the variables

-5y+13

Back to the equation:

-(-5y+13)



We add all the numbers together, and all the variables

-3y-(-5y+13)+18=0

We get rid of parentheses

-3y+5y-13+18=0

We add all the numbers together, and all the variables

2y+5=0

We move all terms containing y to the left, all other terms to the right

2y=-5

y=-5/2

y=-2+1/2

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