12-3(y-3)=6y+8-(y+2)

Solution for 12-3(y-3)=6y+8-(y+2) equation:

12-3(y-3)=6y+8-(y+2)

We move all terms to the left:

12-3(y-3)-(6y+8-(y+2))=0

We multiply parentheses

-3y-(6y+8-(y+2))+9+12=0


We calculate terms in parentheses: -(6y+8-(y+2)), so:

6y+8-(y+2)

determiningTheFunctionDomain
6y-(y+2)+8

We get rid of parentheses

6y-y-2+8

We add all the numbers together, and all the variables

5y+6

Back to the equation:

-(5y+6)


We add all the numbers together, and all the variables

-3y-(5y+6)+21=0

We get rid of parentheses

-3y-5y-6+21=0

We add all the numbers together, and all the variables

-8y+15=0

We move all terms containing y to the left, all other terms to the right

-8y=-15

y=-15/-8

y=1+7/8