12-3x=4(2+x)+33

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Solution for 12-3x=4(2+x)+33 equation: 



12-3x=4(2+x)+33

We move all terms to the left:

12-3x-(4(2+x)+33)=0

We add all the numbers together, and all the variables

-3x-(4(x+2)+33)+12=0



We calculate terms in parentheses: -(4(x+2)+33), so:

4(x+2)+33

We multiply parentheses

4x+8+33

We add all the numbers together, and all the variables

4x+41

Back to the equation:

-(4x+41)



We get rid of parentheses

-3x-4x-41+12=0

We add all the numbers together, and all the variables

-7x-29=0

We move all terms containing x to the left, all other terms to the right

-7x=29

x=29/-7

x=-4+1/7

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