12-4(2a-1)=7+3(a+2)-7a

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Solution for 12-4(2a-1)=7+3(a+2)-7a equation: 



12-4(2a-1)=7+3(a+2)-7a

We move all terms to the left:

12-4(2a-1)-(7+3(a+2)-7a)=0

We multiply parentheses

-8a-(7+3(a+2)-7a)+4+12=0



We calculate terms in parentheses: -(7+3(a+2)-7a), so:

7+3(a+2)-7a

determiningTheFunctionDomain
3(a+2)-7a+7

We add all the numbers together, and all the variables

-7a+3(a+2)+7

We multiply parentheses

-7a+3a+6+7

We add all the numbers together, and all the variables

-4a+13

Back to the equation:

-(-4a+13)



We add all the numbers together, and all the variables

-8a-(-4a+13)+16=0

We get rid of parentheses

-8a+4a-13+16=0

We add all the numbers together, and all the variables

-4a+3=0

We move all terms containing a to the left, all other terms to the right

-4a=-3

a=-3/-4

a=3/4

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