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12-4(3x-1)=4(2x+5)
We move all terms to the left:
12-4(3x-1)-(4(2x+5))=0
We multiply parentheses
-12x-(4(2x+5))+4+12=0
We calculate terms in parentheses: -(4(2x+5)), so:We add all the numbers together, and all the variables
4(2x+5)
We multiply parentheses
8x+20
Back to the equation:
-(8x+20)
-12x-(8x+20)+16=0
We get rid of parentheses
-12x-8x-20+16=0
We add all the numbers together, and all the variables
-20x-4=0
We move all terms containing x to the left, all other terms to the right
-20x=4
x=4/-20
x=-1/5
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