12-4(n+8)=8(n-10)-2n

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Solution for 12-4(n+8)=8(n-10)-2n equation: 



12-4(n+8)=8(n-10)-2n

We move all terms to the left:

12-4(n+8)-(8(n-10)-2n)=0

We multiply parentheses

-4n-(8(n-10)-2n)-32+12=0



We calculate terms in parentheses: -(8(n-10)-2n), so:

8(n-10)-2n

We add all the numbers together, and all the variables

-2n+8(n-10)

We multiply parentheses

-2n+8n-80

We add all the numbers together, and all the variables

6n-80

Back to the equation:

-(6n-80)



We add all the numbers together, and all the variables

-4n-(6n-80)-20=0

We get rid of parentheses

-4n-6n+80-20=0

We add all the numbers together, and all the variables

-10n+60=0

We move all terms containing n to the left, all other terms to the right

-10n=-60

n=-60/-10

n=+6

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