12-4(x+5)=10-2(x+7)

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Solution for 12-4(x+5)=10-2(x+7) equation: 



12-4(x+5)=10-2(x+7)

We move all terms to the left:

12-4(x+5)-(10-2(x+7))=0

We multiply parentheses

-4x-(10-2(x+7))-20+12=0



We calculate terms in parentheses: -(10-2(x+7)), so:

10-2(x+7)

determiningTheFunctionDomain
-2(x+7)+10

We multiply parentheses

-2x-14+10

We add all the numbers together, and all the variables

-2x-4

Back to the equation:

-(-2x-4)



We add all the numbers together, and all the variables

-4x-(-2x-4)-8=0

We get rid of parentheses

-4x+2x+4-8=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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