12-4n-2(n-1)=4(n+4)

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Solution for 12-4n-2(n-1)=4(n+4) equation:


Simplifying
12 + -4n + -2(n + -1) = 4(n + 4)

Reorder the terms:
12 + -4n + -2(-1 + n) = 4(n + 4)
12 + -4n + (-1 * -2 + n * -2) = 4(n + 4)
12 + -4n + (2 + -2n) = 4(n + 4)

Reorder the terms:
12 + 2 + -4n + -2n = 4(n + 4)

Combine like terms: 12 + 2 = 14
14 + -4n + -2n = 4(n + 4)

Combine like terms: -4n + -2n = -6n
14 + -6n = 4(n + 4)

Reorder the terms:
14 + -6n = 4(4 + n)
14 + -6n = (4 * 4 + n * 4)
14 + -6n = (16 + 4n)

Solving
14 + -6n = 16 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
14 + -6n + -4n = 16 + 4n + -4n

Combine like terms: -6n + -4n = -10n
14 + -10n = 16 + 4n + -4n

Combine like terms: 4n + -4n = 0
14 + -10n = 16 + 0
14 + -10n = 16

Add '-14' to each side of the equation.
14 + -14 + -10n = 16 + -14

Combine like terms: 14 + -14 = 0
0 + -10n = 16 + -14
-10n = 16 + -14

Combine like terms: 16 + -14 = 2
-10n = 2

Divide each side by '-10'.
n = -0.2

Simplifying
n = -0.2

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