12-4x(1-x)=x2-2x-7

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Solution for 12-4x(1-x)=x2-2x-7 equation: 



12-4x(1-x)=x2-2x-7

We move all terms to the left:

12-4x(1-x)-(x2-2x-7)=0

We add all the numbers together, and all the variables

-(+x^2-2x-7)-4x(-1x+1)+12=0

We multiply parentheses

-(+x^2-2x-7)+4x^2-4x+12=0

We get rid of parentheses

-x^2+4x^2+2x-4x+7+12=0

We add all the numbers together, and all the variables

3x^2-2x+19=0

a = 3; b = -2; c = +19;
Δ = b2-4ac
Δ = -22-4·3·19
Δ = -224
Delta is less than zero, so there is no solution for the equation

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