12-4x-18=(36+4x)+(18-6x)

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Solution for 12-4x-18=(36+4x)+(18-6x) equation: 



12-4x-18=(36+4x)+(18-6x)

We move all terms to the left:

12-4x-18-((36+4x)+(18-6x))=0

We add all the numbers together, and all the variables

-4x-((4x+36)+(-6x+18))+12-18=0

We add all the numbers together, and all the variables

-4x-((4x+36)+(-6x+18))-6=0



We calculate terms in parentheses: -((4x+36)+(-6x+18)), so:

(4x+36)+(-6x+18)

We get rid of parentheses

4x-6x+36+18

We add all the numbers together, and all the variables

-2x+54

Back to the equation:

-(-2x+54)



We get rid of parentheses

-4x+2x-54-6=0

We add all the numbers together, and all the variables

-2x-60=0

We move all terms containing x to the left, all other terms to the right

-2x=60

x=60/-2

x=-30

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