12-4y=2(y+8)

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Solution for 12-4y=2(y+8) equation: 



12-4y=2(y+8)

We move all terms to the left:

12-4y-(2(y+8))=0



We calculate terms in parentheses: -(2(y+8)), so:

2(y+8)

We multiply parentheses

2y+16

Back to the equation:

-(2y+16)



We get rid of parentheses

-4y-2y-16+12=0

We add all the numbers together, and all the variables

-6y-4=0

We move all terms containing y to the left, all other terms to the right

-6y=4

y=4/-6

y=-2/3

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