12-5(3-2x)=7x+12

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Solution for 12-5(3-2x)=7x+12 equation: 



12-5(3-2x)=7x+12

We move all terms to the left:

12-5(3-2x)-(7x+12)=0

We add all the numbers together, and all the variables

-5(-2x+3)-(7x+12)+12=0

We multiply parentheses

10x-(7x+12)-15+12=0

We get rid of parentheses

10x-7x-12-15+12=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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