12-5(3t-4)=8(-2t+11)

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Solution for 12-5(3t-4)=8(-2t+11) equation: 



12-5(3t-4)=8(-2t+11)

We move all terms to the left:

12-5(3t-4)-(8(-2t+11))=0

We multiply parentheses

-15t-(8(-2t+11))+20+12=0



We calculate terms in parentheses: -(8(-2t+11)), so:

8(-2t+11)

We multiply parentheses

-16t+88

Back to the equation:

-(-16t+88)



We add all the numbers together, and all the variables

-15t-(-16t+88)+32=0

We get rid of parentheses

-15t+16t-88+32=0

We add all the numbers together, and all the variables

t-56=0

We move all terms containing t to the left, all other terms to the right

t=56

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