12-5(m+4)=-10(m-8)-6m

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Solution for 12-5(m+4)=-10(m-8)-6m equation: 



12-5(m+4)=-10(m-8)-6m

We move all terms to the left:

12-5(m+4)-(-10(m-8)-6m)=0

We multiply parentheses

-5m-(-10(m-8)-6m)-20+12=0



We calculate terms in parentheses: -(-10(m-8)-6m), so:

-10(m-8)-6m

We add all the numbers together, and all the variables

-6m-10(m-8)

We multiply parentheses

-6m-10m+80

We add all the numbers together, and all the variables

-16m+80

Back to the equation:

-(-16m+80)



We add all the numbers together, and all the variables

-5m-(-16m+80)-8=0

We get rid of parentheses

-5m+16m-80-8=0

We add all the numbers together, and all the variables

11m-88=0

We move all terms containing m to the left, all other terms to the right

11m=88

m=88/11

m=8

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