12-5(z+2)=8+z

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Solution for 12-5(z+2)=8+z equation: 



12-5(z+2)=8+z

We move all terms to the left:

12-5(z+2)-(8+z)=0

We add all the numbers together, and all the variables

-5(z+2)-(z+8)+12=0

We multiply parentheses

-5z-(z+8)-10+12=0

We get rid of parentheses

-5z-z-8-10+12=0

We add all the numbers together, and all the variables

-6z-6=0

We move all terms containing z to the left, all other terms to the right

-6z=6

z=6/-6

z=-1

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