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12-5/1r=2r+1
We move all terms to the left:
12-5/1r-(2r+1)=0
Domain of the equation: 1r!=0We get rid of parentheses
r∈R
-5/1r-2r-1+12=0
We multiply all the terms by the denominator
-2r*1r-1*1r+12*1r-5=0
Wy multiply elements
-2r^2-1r+12r-5=0
We add all the numbers together, and all the variables
-2r^2+11r-5=0
a = -2; b = 11; c = -5;
Δ = b2-4ac
Δ = 112-4·(-2)·(-5)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-9}{2*-2}=\frac{-20}{-4} =+5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+9}{2*-2}=\frac{-2}{-4} =1/2 $
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