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12-5a=2-(8+2a)
We move all terms to the left:
12-5a-(2-(8+2a))=0
We add all the numbers together, and all the variables
-5a-(2-(2a+8))+12=0
We calculate terms in parentheses: -(2-(2a+8)), so:We get rid of parentheses
2-(2a+8)
determiningTheFunctionDomain -(2a+8)+2
We get rid of parentheses
-2a-8+2
We add all the numbers together, and all the variables
-2a-6
Back to the equation:
-(-2a-6)
-5a+2a+6+12=0
We add all the numbers together, and all the variables
-3a+18=0
We move all terms containing a to the left, all other terms to the right
-3a=-18
a=-18/-3
a=+6
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