12-5x=4+(4+x)

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Solution for 12-5x=4+(4+x) equation: 



12-5x=4+(4+x)

We move all terms to the left:

12-5x-(4+(4+x))=0

We add all the numbers together, and all the variables

-5x-(4+(x+4))+12=0



We calculate terms in parentheses: -(4+(x+4)), so:

4+(x+4)

determiningTheFunctionDomain
(x+4)+4

We get rid of parentheses

x+4+4

We add all the numbers together, and all the variables

x+8

Back to the equation:

-(x+8)



We get rid of parentheses

-5x-x-8+12=0

We add all the numbers together, and all the variables

-6x+4=0

We move all terms containing x to the left, all other terms to the right

-6x=-4

x=-4/-6

x=2/3

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