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12-6(x-7)=3x+3(x+4)
We move all terms to the left:
12-6(x-7)-(3x+3(x+4))=0
We multiply parentheses
-6x-(3x+3(x+4))+42+12=0
We calculate terms in parentheses: -(3x+3(x+4)), so:We add all the numbers together, and all the variables
3x+3(x+4)
We multiply parentheses
3x+3x+12
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
-6x-(6x+12)+54=0
We get rid of parentheses
-6x-6x-12+54=0
We add all the numbers together, and all the variables
-12x+42=0
We move all terms containing x to the left, all other terms to the right
-12x=-42
x=-42/-12
x=3+1/2
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