12-6z-18=7z+12-4z

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Solution for 12-6z-18=7z+12-4z equation: 



12-6z-18=7z+12-4z

We move all terms to the left:

12-6z-18-(7z+12-4z)=0

We add all the numbers together, and all the variables

-6z-(3z+12)+12-18=0

We add all the numbers together, and all the variables

-6z-(3z+12)-6=0

We get rid of parentheses

-6z-3z-12-6=0

We add all the numbers together, and all the variables

-9z-18=0

We move all terms containing z to the left, all other terms to the right

-9z=18

z=18/-9

z=-2

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