12-8(w+1)=18+-5(w+10)

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Solution for 12-8(w+1)=18+-5(w+10) equation: 



12-8(w+1)=18+-5(w+10)

We move all terms to the left:

12-8(w+1)-(18+-5(w+10))=0

We use the square of the difference formula

-8(w+1)-(18-5(w+10))+12=0

We multiply parentheses

-8w-(18-5(w+10))-8+12=0



We calculate terms in parentheses: -(18-5(w+10)), so:

18-5(w+10)

determiningTheFunctionDomain
-5(w+10)+18

We multiply parentheses

-5w-50+18

We add all the numbers together, and all the variables

-5w-32

Back to the equation:

-(-5w-32)



We add all the numbers together, and all the variables

-8w-(-5w-32)+4=0

We get rid of parentheses

-8w+5w+32+4=0

We add all the numbers together, and all the variables

-3w+36=0

We move all terms containing w to the left, all other terms to the right

-3w=-36

w=-36/-3

w=+12

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