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12-m2=-34
We move all terms to the left:
12-m2-(-34)=0
We add all the numbers together, and all the variables
-1m^2+46=0
a = -1; b = 0; c = +46;
Δ = b2-4ac
Δ = 02-4·(-1)·46
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{46}}{2*-1}=\frac{0-2\sqrt{46}}{-2} =-\frac{2\sqrt{46}}{-2} =-\frac{\sqrt{46}}{-1} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{46}}{2*-1}=\frac{0+2\sqrt{46}}{-2} =\frac{2\sqrt{46}}{-2} =\frac{\sqrt{46}}{-1} $
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