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12-n=1/3n
We move all terms to the left:
12-n-(1/3n)=0
Domain of the equation: 3n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
-n-(+1/3n)+12=0
We add all the numbers together, and all the variables
-1n-(+1/3n)+12=0
We get rid of parentheses
-1n-1/3n+12=0
We multiply all the terms by the denominator
-1n*3n+12*3n-1=0
Wy multiply elements
-3n^2+36n-1=0
a = -3; b = 36; c = -1;
Δ = b2-4ac
Δ = 362-4·(-3)·(-1)
Δ = 1284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1284}=\sqrt{4*321}=\sqrt{4}*\sqrt{321}=2\sqrt{321}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{321}}{2*-3}=\frac{-36-2\sqrt{321}}{-6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{321}}{2*-3}=\frac{-36+2\sqrt{321}}{-6} $
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