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12-x=3(4-2x)
We move all terms to the left:
12-x-(3(4-2x))=0
We add all the numbers together, and all the variables
-x-(3(-2x+4))+12=0
We add all the numbers together, and all the variables
-1x-(3(-2x+4))+12=0
We calculate terms in parentheses: -(3(-2x+4)), so:We get rid of parentheses
3(-2x+4)
We multiply parentheses
-6x+12
Back to the equation:
-(-6x+12)
-1x+6x-12+12=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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