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12-y=1/3y
We move all terms to the left:
12-y-(1/3y)=0
Domain of the equation: 3y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-y-(+1/3y)+12=0
We add all the numbers together, and all the variables
-1y-(+1/3y)+12=0
We get rid of parentheses
-1y-1/3y+12=0
We multiply all the terms by the denominator
-1y*3y+12*3y-1=0
Wy multiply elements
-3y^2+36y-1=0
a = -3; b = 36; c = -1;
Δ = b2-4ac
Δ = 362-4·(-3)·(-1)
Δ = 1284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1284}=\sqrt{4*321}=\sqrt{4}*\sqrt{321}=2\sqrt{321}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{321}}{2*-3}=\frac{-36-2\sqrt{321}}{-6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{321}}{2*-3}=\frac{-36+2\sqrt{321}}{-6} $
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