12.5.2w2-1=0

Solution for 12.5.2w2-1=0 equation:

12.5.2w^2-1=0

We add all the numbers together, and all the variables

2.5w^2-1=0

a = 2.5; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·2.5·(-1)
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10}}{2*2.5}=\frac{0-\sqrt{10}}{5}
=-\frac{\sqrt{}}{5}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10}}{2*2.5}=\frac{0+\sqrt{10}}{5}
=\frac{\sqrt{}}{5}
$