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12/(1+12x)=3
We move all terms to the left:
12/(1+12x)-(3)=0
Domain of the equation: (1+12x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
12x!=-1
x!=-1/12
x!=-1/12
x∈R
12/(12x+1)-3=0
We multiply all the terms by the denominator
-3*(12x+1)+12=0
We multiply parentheses
-36x-3+12=0
We add all the numbers together, and all the variables
-36x+9=0
We move all terms containing x to the left, all other terms to the right
-36x=-9
x=-9/-36
x=1/4
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