12/(19x-4)=3/(5x)

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Solution for 12/(19x-4)=3/(5x) equation:


D( x )

19*x-4 = 0

5*x = 0

19*x-4 = 0

19*x-4 = 0

19*x-4 = 0 // + 4

19*x = 4 // : 19

x = 4/19

5*x = 0

5*x = 0

5*x = 0 // : 5

x = 0

x in (-oo:0) U (0:4/19) U (4/19:+oo)

12/(19*x-4) = 3/(5*x) // - 3/(5*x)

12/(19*x-4)-(3/(5*x)) = 0

12/(19*x-4)+(-3/5)*x^-1 = 0

12/(19*x-4)-3/(5*x) = 0

(5*12*x)/(5*x*(19*x-4))+(-3*(19*x-4))/(5*x*(19*x-4)) = 0

5*12*x-3*(19*x-4) = 0

3*x+12 = 0

(3*x+12)/(5*x*(19*x-4)) = 0

(3*x+12)/(5*x*(19*x-4)) = 0 // * 5*x*(19*x-4)

3*x+12 = 0

3*x+12 = 0 // - 12

3*x = -12 // : 3

x = -12/3

x = -4

x = -4

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