12/(z-3)=15/(z+1)

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Solution for 12/(z-3)=15/(z+1) equation: 


D( z )

z-3 = 0

z+1 = 0

z-3 = 0

z-3 = 0

z-3 = 0 // + 3

z = 3

z+1 = 0

z+1 = 0

z+1 = 0 // - 1

z = -1

z in (-oo:-1) U (-1:3) U (3:+oo)

12/(z-3) = 15/(z+1) // - 15/(z+1)

12/(z-3)-(15/(z+1)) = 0

12/(z-3)-15*(z+1)^-1 = 0

12/(z-3)-15/(z+1) = 0

(12*(z+1))/((z-3)*(z+1))+(-15*(z-3))/((z-3)*(z+1)) = 0

12*(z+1)-15*(z-3) = 0

57-3*z = 0

(57-3*z)/((z-3)*(z+1)) = 0

(57-3*z)/((z-3)*(z+1)) = 0 // * (z-3)*(z+1)

57-3*z = 0

57-3*z = 0 // - 57

-3*z = -57 // : -3

z = -57/(-3)

z = 19

z = 19

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