12/1-9x2=1-3x/1+3x+1+3x/1-3x

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Solution for 12/1-9x2=1-3x/1+3x+1+3x/1-3x equation: 


x in (-oo:+oo)

12/1-(9*x^2) = 3*x-((3*x)/1)+(3*x)/1-(3*x)+1+1 // - 3*x-((3*x)/1)+(3*x)/1-(3*x)+1+1

(3*x)/1-(9*x^2)-(3*x)-((3*x)/1)+3*x+12/1-1-1 = 0

3*x-9*x^2-3*x-3*x+3*x-1-1+12 = 0

-9*x^2 = -10 // : -9

x^2 = 10/9

x^2 = 10/9 // ^ 1/2

abs(x) = (10/9)^(1/2)

x = (10/9)^(1/2) or x = -(10/9)^(1/2)

x in { (10/9)^(1/2), -(10/9)^(1/2) }

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