12/15x-10=2/3x

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Solution for 12/15x-10=2/3x equation:



12/15x-10=2/3x
We move all terms to the left:
12/15x-10-(2/3x)=0
Domain of the equation: 15x!=0
x!=0/15
x!=0
x∈R
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
12/15x-(+2/3x)-10=0
We get rid of parentheses
12/15x-2/3x-10=0
We calculate fractions
36x/45x^2+(-30x)/45x^2-10=0
We multiply all the terms by the denominator
36x+(-30x)-10*45x^2=0
Wy multiply elements
-450x^2+36x+(-30x)=0
We get rid of parentheses
-450x^2+36x-30x=0
We add all the numbers together, and all the variables
-450x^2+6x=0
a = -450; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-450)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-450}=\frac{-12}{-900} =1/75 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-450}=\frac{0}{-900} =0 $

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